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Solution manual of Vector Mechanics for Engineers Statics 8th Edition by Beer, Johnston and Eisenberg by www.cronistalascolonias.com.ar
COSMOS: Complete Online Solutions Manual Organization System
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell The McGraw-Hill Companies.
Chapter 2, Solution 1.
(a)
(b)
We measure: 37 lb,R = 76 =
37 lb=R 76!
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COSMOS: Complete Online Solutions Manual Organization System
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell The McGraw-Hill Companies.
Chapter 2, Solution 2.
(a)
(b)
We measure: 57 lb,R = 86 =
57 lb=R 86!
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COSMOS: Complete Online Solutions Manual Organization System
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell The McGraw-Hill Companies.
Chapter 2, Solution 3.
(a) Parallelogram law:
(b) Triangle rule:
We measure:
kNR =
=
kN=R !
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COSMOS: Complete Online Solutions Manual Organization System
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell The McGraw-Hill Companies.
Chapter 2, Solution 4.
(a) Parallelogram law:
We measure:
kN = 12R =
kN=R 12!
(b) Triangle rule:
We measure:
kN = 12R =
kN=R 12 !
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COSMOS: Complete Online Solutions Manual Organization System
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell The McGraw-Hill Companies.
Chapter 2, Solution 5.
Using the triangle rule and the Law of Sines
(a) sin sin 45
N N
=
sin = = 45 + + = = !
(b) Using the Law of Sines
=
45sin
N
sinbbF
NbbF = !
-
COSMOS: Complete Online Solutions Manual Organization System
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell The McGraw-Hill Companies.
Chapter 2, Solution 6.
Using the triangle rule and the Law of Sines
(a) sin sin 45
N N
=
sin =
=
or = !
(b) 45 + + = = Using the Law of Sines
N
sin sin 45aaF
=
N
sin sin 45aaF
=
or NaaF = !
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COSMOS: Complete Online Solutions Manual Organization System
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell The McGraw-Hill Companies.
Chapter 2, Solution 7.
Using the triangle rule and the Law of Cosines,
Have: 45 = = Then:
( ) ( ) ( )( )2 22 2 cos = + R or NR =
Using the Law of Sines,
sin sin
=
or =
and 90 =
=
(a) = !
(b) kNR = !
-
COSMOS: Complete Online Solutions Manual Organization System
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell The McGraw-Hill Companies.
Chapter 2, Solution 8.
By trigonometry: Law of Sines
2 30sin sin 38 sin
F R
= =
90 28 62 , 62 38 80 = = = = Then:
2 30 lbsin 62 sin 38 sin80
F R= =
or (a) 2 lbF = !
(b) lbR = !
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COSMOS: Complete Online Solutions Manual Organization System
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell The McGraw-Hill Companies.
Chapter 2, Solution 9.
Using the Law of Sines
1 20 lbsin sin 38 sin
F R
= =
90 10 80 , 80 38 62 = = = = Then:
1 20 lbsin80 sin 38 sin 62
F R= =
or (a) 1 lbF = !
(b) lbR = !
-
COSMOS: Complete Online Solutions Manual Organization System
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell The McGraw-Hill Companies.
Chapter 2, Solution
Using the Law of Sines: 60 N 80 Nsin sin10
=
or =
( ) 10 = + =
Then:
80 N
sin sin10R
=
or NR =
(a) = !
(b) NR = !
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COSMOS: Complete Online Solutions Manual Organization System
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell The McGraw-Hill Companies.
Chapter 2, Solution
Using the triangle rule and the Law of Sines
Have: ( ) 35 25 = + =
Then: 80 lb
sin 35 sin sin 25P R
= =
or (a) lbP = !
(b) lbR = !
-
COSMOS: Complete Online Solutions Manual Organization System
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell The McGraw-Hill Companies.
Chapter 2, Solution
Using the triangle rule and the Law of Sines
(a) Have: 80 lb 70 lbsin sin 35
=
sin =
=
or = !
(b) ( ) 35 = + =
Then: 70 lb
sin sin 35R
=
or lbR = !
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COSMOS: Complete Online Solutions Manual Organization System
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell The McGraw-Hill Companies.
Chapter 2, Solution
We observe that force P is minimum when 90 . =
Then:
(a) ( )80 lb sin 35P = or lb=P !
And:
(b) ( )80 lb cos35R = or lb=R !
-
COSMOS: Complete Online Solutions Manual Organization System
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell The McGraw-Hill Companies.
Chapter 2, Solution
For BCT to be a minimum,
R and BCT must be perpendicular.
Thus ( )70 N sin 4BCT = N=
And ( )70 N cos 4R = N=
(a) NBCT = !
(b) NR = !
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COSMOS: Complete Online Solutions Manual Organization System
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell The McGraw-Hill Companies.
Chapter 2, Solution
Using the force triangle and the Laws of Cosines and Sines
We have:
( ) 15 30 = + =
Then: ( ) ( ) ( )( )2 22 15 lb 25 lb 2 15 lb 25 lb cosR = + lb=
or lbR =
and
25 lb lbsin sin =
25 lbsin sin
lb =
=
= Then: 75 + + =
=
lb=R !
-
COSMOS: Complete Online Solutions Manual Organization System
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell The McGraw-Hill Companies.
Chapter 2, Solution
Using the Law of Cosines and the Law of Sines,
( ) ( ) ( )( )2 2 lb 15 lb 2 45 lb 15 lb cosR = + or lbR =
lb 15 lbsin sin
=
or =
lb=R !
www.cronistalascolonias.com.ar
COSMOS: Complete Online Solutions Manual Organization System
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell The McGraw-Hill Companies.
Chapter 2, Solution
25 50 = = Using the Law of Cosines:
( ) ( ) ( )( )2 22 5 kN 8 kN 2 5 kN 8 kN cosR = + or kNR
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