Unzip file before download python

Unzip file before download python

unzip file before download python

There might be a case where you want to download and unzip a file from given URL in your python project. There are multiple ways of doing it. In Python's zipfile module, ZipFile class provides a member function to extract all the contents Until we execute the Save() method, we are working with the XML This data can be a file, a website or whatever you want Python to download. Downloading and Unzippig a Zip File, Zipfile and shutil in python. where you will extract your files doesn't need to exist before, you name it at this moment.

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Python: How to unzip a file | Extract Single, multiple or all files from a ZIP archive

In this article we will discuss different ways to unzip or extract single, multiple or all files from zip archive to current or different directory.

In Python&#;s zipfile module, ZipFile class provides a member function to extract all the contents from a ZIP archive,

www.cronistalascolonias.com.artall(path=None, members=None, pwd=None)
It accepts following arguments :
  • path : location where zip file need to be extracted, if not provided it will extract the contents in current directory.
  • members : list of files to be extracted. It will extract all the files in zip if this argument is not provided.
  • pwd : If zip file is encrypted then pass password in this argument default is None.

Module required :

from zipfile import ZipFile
Let&#;s use this to extract all the contents from zip files.

Extract all files from a zip file to current directory

Suppose we have a zip file &#;www.cronistalascolonias.com.ar&#;. in our current directory, let&#;s see how to extract all files from it.
To unzip it first create a ZipFile object by opening the zip file in read mode and then call extractall() on that object i.e.

# Create a ZipFile Object and load www.cronistalascolonias.com.ar in it with ZipFile(&#;www.cronistalascolonias.com.ar&#;, &#;r&#;) as zipObj: # Extract all the contents of zip file in current directory www.cronistalascolonias.com.artall()
It will extract all the files in zip at current Directory.  If files with same name are already present at extraction location then it will overwrite those files.

Extract all files from a zip file to different directory

To extract all the files from zip file to a different directory, we can pass the destination location as argument in extractall(). Path can be relative or absolute.

# Create a ZipFile Object and load www.cronistalascolonias.com.ar in it with ZipFile(&#;www.cronistalascolonias.com.ar&#;, &#;r&#;) as zipObj: # Extract all the contents of zip file in different directory www.cronistalascolonias.com.artall(&#;temp&#;)
It will extract all the files in &#;www.cronistalascolonias.com.ar&#; in  temp folder.

Extract few files from a large zip file based on condition

Suppose we have a very large zip file and we need a few files from thousand of files in the archive. Unzipping all files from large zip can take minutes. But if are interested in few of the archived files only, then instead of unzipping the whole file we can extract a single file too from the zip file.

In Python&#;s zipfile module, ZipFile class provides a member function to extract a single from a ZIP File,

www.cronistalascolonias.com.art(member, path=None, pwd=None)
It accepts following arguments :
  • member : Full name of file to be extracted. It should one from the list of archived files names returned by www.cronistalascolonias.com.arst()
  • path : location where zip file need to be extracted, if not provided it will extract the file in current directory.
  • pwd : If zip file is encrypted then pass password in this argument default is None.

Let&#;s use this to extract only csv files from a zip file i.e.

# Create a ZipFile Object and load www.cronistalascolonias.com.ar in it with ZipFile(&#;www.cronistalascolonias.com.ar&#;, &#;r&#;) as zipObj: # Get a list of all archived file names from the zip listOfFileNames = www.cronistalascolonias.com.arst() # Iterate over the file names for fileName in listOfFileNames: # Check filename endswith csv if www.cronistalascolonias.com.arth(&#;.csv&#;): # Extract a single file from zip www.cronistalascolonias.com.art(fileName, &#;temp_csv&#;)
It will extract only csv files from given zip archive.

Complete example is as follows,

from zipfile import ZipFile def main(): print(&#;Extract all files in ZIP to current directory&#;) # Create a ZipFile Object and load www.cronistalascolonias.com.ar in it with ZipFile(&#;www.cronistalascolonias.com.ar&#;, &#;r&#;) as zipObj: # Extract all the contents of zip file in current directory www.cronistalascolonias.com.artall() print(&#;Extract all files in ZIP to different directory&#;) # Create a ZipFile Object and load www.cronistalascolonias.com.ar in it with ZipFile(&#;www.cronistalascolonias.com.ar&#;, &#;r&#;) as zipObj: # Extract all the contents of zip file in different directory www.cronistalascolonias.com.artall(&#;temp&#;) print(&#;Extract single file from ZIP&#;) # Create a ZipFile Object and load www.cronistalascolonias.com.ar in it with ZipFile(&#;www.cronistalascolonias.com.ar&#;, &#;r&#;) as zipObj: # Get a list of all archived file names from the zip listOfFileNames = www.cronistalascolonias.com.arst() # Iterate over the file names for fileName in listOfFileNames: # Check filename endswith csv if www.cronistalascolonias.com.arth(&#;.csv&#;): # Extract a single file from zip www.cronistalascolonias.com.art(fileName, &#;temp_csv&#;) if __name__ == &#;__main__&#;: main()
 

 

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Источник: www.cronistalascolonias.com.ar

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